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1/3(x+6)=2/3(x+9)
We move all terms to the left:
1/3(x+6)-(2/3(x+9))=0
Domain of the equation: 3(x+6)!=0
x∈R
Domain of the equation: 3(x+9))!=0We calculate fractions
x∈R
(3xx/(3(x+6)*3(x+9)))+(-6xx/(3(x+6)*3(x+9)))=0
We calculate terms in parentheses: +(3xx/(3(x+6)*3(x+9))), so:
3xx/(3(x+6)*3(x+9))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-6xx/(3(x+6)*3(x+9))), so:We get rid of parentheses
-6xx/(3(x+6)*3(x+9))
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
3xx-6xx=0
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