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1/3(x+6)=2/3(x-9(
We move all terms to the left:
1/3(x+6)-(2/3(x-9()=0
Domain of the equation: 3(x+6)!=0
x∈R
Domain of the equation: 3(x-9()!=0We calculate fractions
x∈R
(3xx/(3(x+6)*3(x-9())+(-6xx/(3(x+6)*3(x-9())=0
We calculate terms in parentheses: +(3xx/(3(x+6)*3(x-9())+(-6xx/(3(x+6)*3(x-9()), so:
3xx/(3(x+6)*3(x-9())+(-6xx/(3(x+6)*3(x-9()
We can not solve this equation
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