1/3(x-1)-1=1/2(x+1)

Solution for 1/3(x-1)-1=1/2(x+1) equation:

1/3(x-1)-1=1/2(x+1)

We move all terms to the left:

1/3(x-1)-1-(1/2(x+1))=0


Domain of the equation: 3(x-1)!=0

x∈R



Domain of the equation: 2(x+1))!=0

x∈R


We calculate fractions


(2xx/(3(x-1)*2(x+1)))+(-3xx/(3(x-1)*2(x+1)))-1=0


We calculate terms in parentheses: +(2xx/(3(x-1)*2(x+1))), so:

2xx/(3(x-1)*2(x+1))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-3xx/(3(x-1)*2(x+1))), so:

-3xx/(3(x-1)*2(x+1))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2xx-3xx-1=0

We move all terms containing x to the left, all other terms to the right

2xx-3xx=1