1/3(x-1/4)=1/8+1/3x

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Solution for 1/3(x-1/4)=1/8+1/3x equation:


x in (-oo:+oo)

(1/3)*(x-(1/4)) = (1/3)*x+1/8 // - (1/3)*x+1/8

(1/3)*(x-(1/4))-((1/3)*x)-(1/8) = 0

(1/3)*(x-1/4)+(-1/3)*x-1/8 = 0

1/3*(x-1/4)-x/3-1/8 = 0

(1/3*3*8*(x-1/4))/(3*8)+(8*(-x))/(3*8)+(-1*3)/(3*8) = 0

1/3*3*8*(x-1/4)+8*(-x)-1*3 = 0

-3-2 = 0

-5 = 0

-5/(3*8) = 0

-5/(3*8) = 0 // * 3*8

-5 = 0

x belongs to the empty set

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