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1/3(x-12)=2x+6
We move all terms to the left:
1/3(x-12)-(2x+6)=0
Domain of the equation: 3(x-12)!=0We get rid of parentheses
x∈R
1/3(x-12)-2x-6=0
We multiply all the terms by the denominator
-2x*3(x-12)-6*3(x-12)+1=0
Wy multiply elements
-6x^2(x-18x(x+1=0
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