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1/3(x-2)=1/4(x+3)
We move all terms to the left:
1/3(x-2)-(1/4(x+3))=0
Domain of the equation: 3(x-2)!=0
x∈R
Domain of the equation: 4(x+3))!=0We calculate fractions
x∈R
(4xx/(3(x-2)*4(x+3)))+(-3xx/(3(x-2)*4(x+3)))=0
We calculate terms in parentheses: +(4xx/(3(x-2)*4(x+3))), so:
4xx/(3(x-2)*4(x+3))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-3xx/(3(x-2)*4(x+3))), so:We get rid of parentheses
-3xx/(3(x-2)*4(x+3))
We multiply all the terms by the denominator
-3xx
Back to the equation:
+(-3xx)
4xx-3xx=0
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