1/3(x-2)=1/5(x+4)2

Solution for 1/3(x-2)=1/5(x+4)2 equation:

1/3(x-2)=1/5(x+4)2

We move all terms to the left:

1/3(x-2)-(1/5(x+4)2)=0


Domain of the equation: 3(x-2)!=0

x∈R



Domain of the equation: 5(x+4)2)!=0

x∈R


We calculate fractions


(5xx/(3(x-2)*5(x+4)2))+(-3xx/(3(x-2)*5(x+4)2))=0


We calculate terms in parentheses: +(5xx/(3(x-2)*5(x+4)2)), so:

5xx/(3(x-2)*5(x+4)2)

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)



We calculate terms in parentheses: +(-3xx/(3(x-2)*5(x+4)2)), so:

-3xx/(3(x-2)*5(x+4)2)

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

5xx-3xx=0