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1/3(x-3)+1/6(2x-6)=x-3
We move all terms to the left:
1/3(x-3)+1/6(2x-6)-(x-3)=0
Domain of the equation: 3(x-3)!=0
x∈R
Domain of the equation: 6(2x-6)!=0We get rid of parentheses
x∈R
1/3(x-3)+1/6(2x-6)-x+3=0
We calculate fractions
-x+(6x2/(3(x-3)*6(2x-6))+(3xx/(3(x-3)*6(2x-6))+3=0
We can not solve this equation
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