1/3(x-3)+5/6(x+2)=x-1

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Solution for 1/3(x-3)+5/6(x+2)=x-1 equation: 



1/3(x-3)+5/6(x+2)=x-1

We move all terms to the left:

1/3(x-3)+5/6(x+2)-(x-1)=0



Domain of the equation: 3(x-3)!=0

x∈R





Domain of the equation: 6(x+2)!=0

x∈R



We get rid of parentheses

1/3(x-3)+5/6(x+2)-x+1=0

We calculate fractions


-x+(6xx/(3(x-3)*6(x+2))+(15xx/(3(x-3)*6(x+2))+1=0

We can not solve this equation

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