1/3(x-4)-7/2(3x-3)=5/6

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Solution for 1/3(x-4)-7/2(3x-3)=5/6 equation:



1/3(x-4)-7/2(3x-3)=5/6
We move all terms to the left:
1/3(x-4)-7/2(3x-3)-(5/6)=0
Domain of the equation: 3(x-4)!=0
x∈R
Domain of the equation: 2(3x-3)!=0
x∈R
We add all the numbers together, and all the variables
1/3(x-4)-7/2(3x-3)-(+5/6)=0
We get rid of parentheses
1/3(x-4)-7/2(3x-3)-5/6=0
We calculate fractions
(12x3/(3(x-4)*2(3x-3)*6)+(-126xx/(3(x-4)*2(3x-3)*6)+(-30x^2x/(3(x-4)*2(3x-3)*6)=0
We calculate terms in parentheses: +(12x3/(3(x-4)*2(3x-3)*6)+(-126xx/(3(x-4)*2(3x-3)*6)+(-30x^2x/(3(x-4)*2(3x-3)*6), so:
12x3/(3(x-4)*2(3x-3)*6)+(-126xx/(3(x-4)*2(3x-3)*6)+(-30x^2x/(3(x-4)*2(3x-3)*6
We can not solve this equation

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