1/3(x-6)+1/2(x+5)=5/3

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Solution for 1/3(x-6)+1/2(x+5)=5/3 equation: 



1/3(x-6)+1/2(x+5)=5/3

We move all terms to the left:

1/3(x-6)+1/2(x+5)-(5/3)=0



Domain of the equation: 3(x-6)!=0

x∈R





Domain of the equation: 2(x+5)!=0

x∈R



We add all the numbers together, and all the variables

1/3(x-6)+1/2(x+5)-(+5/3)=0

We get rid of parentheses

1/3(x-6)+1/2(x+5)-5/3=0

We calculate fractions


(2xx/(3(x-6)*2(x+5)*3)+(9xx/(3(x-6)*2(x+5)*3)+(-10xx/(3(x-6)*2(x+5)*3)=0



We calculate terms in parentheses: +(2xx/(3(x-6)*2(x+5)*3)+(9xx/(3(x-6)*2(x+5)*3)+(-10xx/(3(x-6)*2(x+5)*3), so:

2xx/(3(x-6)*2(x+5)*3)+(9xx/(3(x-6)*2(x+5)*3)+(-10xx/(3(x-6)*2(x+5)*3

We can not solve this equation

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