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1/3(x-6)=5-1/2(3x+1)
We move all terms to the left:
1/3(x-6)-(5-1/2(3x+1))=0
Domain of the equation: 3(x-6)!=0
x∈R
Domain of the equation: 2(3x+1))!=0We calculate fractions
x∈R
(2x3/(3(x-6)*2(3x+1)))+(-(-3xx)/(3(x-6)*2(3x+1)))=0
We calculate terms in parentheses: +(2x3/(3(x-6)*2(3x+1))), so:
2x3/(3(x-6)*2(3x+1))
We multiply all the terms by the denominator
2x3
We add all the numbers together, and all the variables
2x^3
We do not support expression: x^3
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