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1/3(x-9)+1/3(x+3)=x-5
We move all terms to the left:
1/3(x-9)+1/3(x+3)-(x-5)=0
Domain of the equation: 3(x-9)!=0
x∈R
Domain of the equation: 3(x+3)!=0We get rid of parentheses
x∈R
1/3(x-9)+1/3(x+3)-x+5=0
We calculate fractions
-x+(3xx/(3(x-9)*3(x+3))+(3xx/(3(x-9)*3(x+3))+5=0
We can not solve this equation
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