1/3(y+3)=1/5(y-3)

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Solution for 1/3(y+3)=1/5(y-3) equation: 



1/3(y+3)=1/5(y-3)

We move all terms to the left:

1/3(y+3)-(1/5(y-3))=0



Domain of the equation: 3(y+3)!=0

y∈R





Domain of the equation: 5(y-3))!=0

y∈R



We calculate fractions


(5yy/(3(y+3)*5(y-3)))+(-3yy/(3(y+3)*5(y-3)))=0



We calculate terms in parentheses: +(5yy/(3(y+3)*5(y-3))), so:

5yy/(3(y+3)*5(y-3))

We multiply all the terms by the denominator


5yy

Back to the equation:

+(5yy)





We calculate terms in parentheses: +(-3yy/(3(y+3)*5(y-3))), so:

-3yy/(3(y+3)*5(y-3))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)



We get rid of parentheses

5yy-3yy=0

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