1/3(y+4)+6=1/4(3y-2)-3

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Solution for 1/3(y+4)+6=1/4(3y-2)-3 equation: 



1/3(y+4)+6=1/4(3y-2)-3

We move all terms to the left:

1/3(y+4)+6-(1/4(3y-2)-3)=0



Domain of the equation: 3(y+4)!=0

y∈R





Domain of the equation: 4(3y-2)-3)!=0

y∈R



We calculate fractions


(4y3/(3(y+4)*4(3y-2))+(-3yy/(3(y+4)*4(3y-2))+6=0

We can not solve this equation

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