1/3(y-1)=1/2(y-3)

Solution for 1/3(y-1)=1/2(y-3) equation:

1/3(y-1)=1/2(y-3)

We move all terms to the left:

1/3(y-1)-(1/2(y-3))=0


Domain of the equation: 3(y-1)!=0

y∈R



Domain of the equation: 2(y-3))!=0

y∈R


We calculate fractions


(2yy/(3(y-1)*2(y-3)))+(-3yy/(3(y-1)*2(y-3)))=0


We calculate terms in parentheses: +(2yy/(3(y-1)*2(y-3))), so:

2yy/(3(y-1)*2(y-3))

We multiply all the terms by the denominator


2yy

Back to the equation:

+(2yy)



We calculate terms in parentheses: +(-3yy/(3(y-1)*2(y-3))), so:

-3yy/(3(y-1)*2(y-3))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)


We get rid of parentheses

2yy-3yy=0