1/3(y-3)-1/4(y-4)=1/6

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Solution for 1/3(y-3)-1/4(y-4)=1/6 equation: 



1/3(y-3)-1/4(y-4)=1/6

We move all terms to the left:

1/3(y-3)-1/4(y-4)-(1/6)=0



Domain of the equation: 3(y-3)!=0

y∈R





Domain of the equation: 4(y-4)!=0

y∈R



We add all the numbers together, and all the variables

1/3(y-3)-1/4(y-4)-(+1/6)=0

We get rid of parentheses

1/3(y-3)-1/4(y-4)-1/6=0

We calculate fractions


(24yy/(3(y-3)*4(y-4)*6)+(-18yy/(3(y-3)*4(y-4)*6)+(-12y^2y/(3(y-3)*4(y-4)*6)=0



We calculate terms in parentheses: +(24yy/(3(y-3)*4(y-4)*6)+(-18yy/(3(y-3)*4(y-4)*6)+(-12y^2y/(3(y-3)*4(y-4)*6), so:

24yy/(3(y-3)*4(y-4)*6)+(-18yy/(3(y-3)*4(y-4)*6)+(-12y^2y/(3(y-3)*4(y-4)*6

We can not solve this equation

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