1/3(y-3)=1/4(y+4)

Solution for 1/3(y-3)=1/4(y+4) equation:

1/3(y-3)=1/4(y+4)

We move all terms to the left:

1/3(y-3)-(1/4(y+4))=0


Domain of the equation: 3(y-3)!=0

y∈R



Domain of the equation: 4(y+4))!=0

y∈R


We calculate fractions


(4yy/(3(y-3)*4(y+4)))+(-3yy/(3(y-3)*4(y+4)))=0


We calculate terms in parentheses: +(4yy/(3(y-3)*4(y+4))), so:

4yy/(3(y-3)*4(y+4))

We multiply all the terms by the denominator


4yy

Back to the equation:

+(4yy)



We calculate terms in parentheses: +(-3yy/(3(y-3)*4(y+4))), so:

-3yy/(3(y-3)*4(y+4))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)


We get rid of parentheses

4yy-3yy=0