1/3(y-3)=1/6(y+4)

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Solution for 1/3(y-3)=1/6(y+4) equation: 



1/3(y-3)=1/6(y+4)

We move all terms to the left:

1/3(y-3)-(1/6(y+4))=0



Domain of the equation: 3(y-3)!=0

y∈R





Domain of the equation: 6(y+4))!=0

y∈R



We calculate fractions


(6yy/(3(y-3)*6(y+4)))+(-3yy/(3(y-3)*6(y+4)))=0



We calculate terms in parentheses: +(6yy/(3(y-3)*6(y+4))), so:

6yy/(3(y-3)*6(y+4))

We multiply all the terms by the denominator


6yy

Back to the equation:

+(6yy)





We calculate terms in parentheses: +(-3yy/(3(y-3)*6(y+4))), so:

-3yy/(3(y-3)*6(y+4))

We multiply all the terms by the denominator


-3yy

Back to the equation:

+(-3yy)



We get rid of parentheses

6yy-3yy=0

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