1/3(y-6)=4y-2/3(2-y)

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Solution for 1/3(y-6)=4y-2/3(2-y) equation: 



1/3(y-6)=4y-2/3(2-y)

We move all terms to the left:

1/3(y-6)-(4y-2/3(2-y))=0



Domain of the equation: 3(y-6)!=0

y∈R





Domain of the equation: 3(2-y))!=0

y∈R



We add all the numbers together, and all the variables

1/3(y-6)-(4y-2/3(-1y+2))=0

We calculate fractions


(3y(-)/(3(y-6)*3(-1y+2)))+(-(4y-6yy)/(3(y-6)*3(-1y+2)))=0



We calculate terms in parentheses: +(3y(-)/(3(y-6)*3(-1y+2))), so:

3y(-)/(3(y-6)*3(-1y+2))

We add all the numbers together, and all the variables

3y0/(3(y-6)*3(-1y+2))

We multiply all the terms by the denominator


3y0

We add all the numbers together, and all the variables

3y

Back to the equation:

+(3y)





We calculate terms in parentheses: +(-(4y-6yy)/(3(y-6)*3(-1y+2))), so:

-(4y-6yy)/(3(y-6)*3(-1y+2))

We add all the numbers together, and all the variables

-(+4y-6yy)/(3(y-6)*3(-1y+2))

We multiply all the terms by the denominator


-(+4y-6yy)

We get rid of parentheses

-4y+6yy

Back to the equation:

+(-4y+6yy)



We get rid of parentheses

3y-4y+6yy=0

We add all the numbers together, and all the variables

-1y+6yy=0

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