1/3(y-9)=-4y+13/3y-3

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Solution for 1/3(y-9)=-4y+13/3y-3 equation: 



1/3(y-9)=-4y+13/3y-3

We move all terms to the left:

1/3(y-9)-(-4y+13/3y-3)=0



Domain of the equation: 3(y-9)!=0

y∈R





Domain of the equation: 3y-3)!=0

y∈R



We get rid of parentheses

1/3(y-9)+4y-13/3y+3=0

We calculate fractions


4y+3y/(9y^2-81y)+(-39yy/(9y^2-81y)+3=0

We calculate fractions

We do not support eypression: y^3

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