1/3(z)=2

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Solution for 1/3(z)=2 equation: 



1/3(z)=2

We move all terms to the left:

1/3(z)-(2)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We multiply all the terms by the denominator


-2*3z+1=0

Wy multiply elements

-6z+1=0

We move all terms containing z to the left, all other terms to the right

-6z=-1

z=-1/-6

z=1/6

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