1/3(z+12)=5

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Solution for 1/3(z+12)=5 equation: 



1/3(z+12)=5

We move all terms to the left:

1/3(z+12)-(5)=0



Domain of the equation: 3(z+12)!=0

z∈R



We multiply all the terms by the denominator


-5*3(z+12)+1=0

Wy multiply elements

-15z(z+1=0

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