1/3(z+9)=1/4(-z+2)

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Solution for 1/3(z+9)=1/4(-z+2) equation: 



1/3(z+9)=1/4(-z+2)

We move all terms to the left:

1/3(z+9)-(1/4(-z+2))=0



Domain of the equation: 3(z+9)!=0

z∈R





Domain of the equation: 4(-z+2))!=0

z∈R



We add all the numbers together, and all the variables

1/3(z+9)-(1/4(-1z+2))=0

We calculate fractions


(4z(-)/(3(z+9)*4(-1z+2)))+(-3zz/(3(z+9)*4(-1z+2)))=0



We calculate terms in parentheses: +(4z(-)/(3(z+9)*4(-1z+2))), so:

4z(-)/(3(z+9)*4(-1z+2))

We add all the numbers together, and all the variables

4z0/(3(z+9)*4(-1z+2))

We multiply all the terms by the denominator


4z0

We add all the numbers together, and all the variables

4z

Back to the equation:

+(4z)





We calculate terms in parentheses: +(-3zz/(3(z+9)*4(-1z+2))), so:

-3zz/(3(z+9)*4(-1z+2))

We multiply all the terms by the denominator


-3zz

Back to the equation:

+(-3zz)



We get rid of parentheses

4z-3zz=0

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