1/3(z-10)=40

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Solution for 1/3(z-10)=40 equation: 



1/3(z-10)=40

We move all terms to the left:

1/3(z-10)-(40)=0



Domain of the equation: 3(z-10)!=0

z∈R



We multiply all the terms by the denominator


-40*3(z-10)+1=0

Wy multiply elements

-120z(z+1=0

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