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1/3(1-2z)=1
We move all terms to the left:
1/3(1-2z)-(1)=0
Domain of the equation: 3(1-2z)!=0We add all the numbers together, and all the variables
z∈R
1/3(-2z+1)-1=0
We multiply all the terms by the denominator
-1*3(-2z+1)+1=0
Wy multiply elements
-3z(-+1=0
We use the square of the difference formula
-3z(-1=0
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