1/3*(4-x)=1/2*(x+4)

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Solution for 1/3*(4-x)=1/2*(x+4) equation: 



1/3(4-x)=1/2(x+4)

We move all terms to the left:

1/3(4-x)-(1/2(x+4))=0



Domain of the equation: 3(4-x)!=0

x∈R





Domain of the equation: 2(x+4))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-1x+4)-(1/2(x+4))=0

We calculate fractions


(2xx/(3(-1x+4)*2(x+4)))+(-3x0/(3(-1x+4)*2(x+4)))=0



We calculate terms in parentheses: +(2xx/(3(-1x+4)*2(x+4))), so:

2xx/(3(-1x+4)*2(x+4))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-3x0/(3(-1x+4)*2(x+4))), so:

-3x0/(3(-1x+4)*2(x+4))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

2xx-3x=0

We add all the numbers together, and all the variables

-3x+2xx=0

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