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1/3(4a+1)=1/2a
We move all terms to the left:
1/3(4a+1)-(1/2a)=0
Domain of the equation: 3(4a+1)!=0
a∈R
Domain of the equation: 2a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1/3(4a+1)-(+1/2a)=0
We get rid of parentheses
1/3(4a+1)-1/2a=0
We calculate fractions
2a/(24a^2+6a)+(-3a4/(24a^2+6a)=0
We calculate terms in parentheses: +(-3a4/(24a^2+6a), so:
-3a4/(24a^2+6a
We multiply all the terms by the denominator
-3a4
We add all the numbers together, and all the variables
-3a^4
We do not support eapression: a^4
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