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1/3+2/3q=5/3
We move all terms to the left:
1/3+2/3q-(5/3)=0
Domain of the equation: 3q!=0We add all the numbers together, and all the variables
q!=0/3
q!=0
q∈R
2/3q+1/3-(+5/3)=0
We get rid of parentheses
2/3q+1/3-5/3=0
We calculate fractions
=0
q=0/1
q=0
Równanie nie ma rozwiązania
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