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1/3+5t=9
We move all terms to the left:
1/3+5t-(9)=0
determiningTheFunctionDomain 5t-9+1/3=0
We multiply all the terms by the denominator
5t*3+1-9*3=0
We add all the numbers together, and all the variables
5t*3-26=0
Wy multiply elements
15t-26=0
We move all terms containing t to the left, all other terms to the right
15t=26
t=26/15
t=1+11/15
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