1/3-1/A/3-A/3

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Solution for 1/3-1/A/3-A/3 equation: 


D( A )

A = 0

A = 0

A = 0

A in (-oo:0) U (0:+oo)

1/3-(A/3)-((1/A)/3) = 0

(-1/3)*A^-1-(A/3)+1/3 = 0

1/3*A^0-1/3*A^1-1/3*A^-1 = 0

(1/3*A^1-1/3*A^2-1/3*A^0)/(A^1) = 0 // * A^2

A^1*(1/3*A^1-1/3*A^2-1/3*A^0) = 0

A^1

(-1/3)*A^2+(1/3)*A-1/3 = 0

(-1/3)*A^2+(1/3)*A-1/3 = 0

DELTA = (1/3)^2-(4*(-1/3)*(-1/3))

DELTA = -1/3

DELTA < 0

A in { } 

A belongs to the empty set

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