1/3-4(7x-3)=5/8+7(11+4x)

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Solution for 1/3-4(7x-3)=5/8+7(11+4x) equation: 



1/3-4(7x-3)=5/8+7(11+4x)

We move all terms to the left:

1/3-4(7x-3)-(5/8+7(11+4x))=0



Domain of the equation: 8+7(11+4x))!=0

We move all terms containing x to the left, all other terms to the right

7(11+4x))!=-8

x∈R



We add all the numbers together, and all the variables

-4(7x-3)-(5/8+7(4x+11))+1/3=0

We multiply parentheses

-28x-(5/8+7(4x+11))+12+1/3=0

We calculate fractions


-28x+()/(7(4x+11))*3+8)+(7(4x+11))+1*8)/(7(4x+12+11))*3+8)=0

We add all the numbers together, and all the variables

-28x+()/(7(4x+11))*3+8)+(7(4x+11))+1*8)/(7(4x+23))*3+8)=0

We add all the numbers together, and all the variables

-28x+()/(7(4x+11))*3+8)+(7(4x+11))+1*8)/(7(4x=0

We calculate fractions


-28x+(()*(74x/((7(4x+11))*3*(74x+8+(7(4x+11))+1*8)*(74x/((7(4x+11))*3*(74x=0

We can not solve this equation

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