1/3-4/3t=7/t

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Solution for 1/3-4/3t=7/t equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1/3-((4/3)*t) = 7/t // - 7/t

1/3-((4/3)*t)-(7/t) = 0

(-4/3)*t-7*t^-1+1/3 = 0

1/3*t^0-4/3*t^1-7*t^-1 = 0

(1/3*t^1-4/3*t^2-7*t^0)/(t^1) = 0 // * t^2

t^1*(1/3*t^1-4/3*t^2-7*t^0) = 0

t^1

(-4/3)*t^2+(1/3)*t-7 = 0

(-4/3)*t^2+(1/3)*t-7 = 0

DELTA = (1/3)^2-(-7*4*(-4/3))

DELTA = -335/9

DELTA < 0

t in { } 

t belongs to the empty set

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