1/3-5/3x=7/x

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Solution for 1/3-5/3x=7/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/3-((5/3)*x) = 7/x // - 7/x

1/3-((5/3)*x)-(7/x) = 0

(-5/3)*x-7*x^-1+1/3 = 0

1/3*x^0-5/3*x^1-7*x^-1 = 0

(1/3*x^1-5/3*x^2-7*x^0)/(x^1) = 0 // * x^2

x^1*(1/3*x^1-5/3*x^2-7*x^0) = 0

x^1

(-5/3)*x^2+(1/3)*x-7 = 0

(-5/3)*x^2+(1/3)*x-7 = 0

DELTA = (1/3)^2-(-7*4*(-5/3))

DELTA = -419/9

DELTA < 0

x in { } 

x belongs to the empty set

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