1/3-x=(1/3+x)+1/x

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Solution for 1/3-x=(1/3+x)+1/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/3-x = x+1/x+1/3 // - x+1/x+1/3

1/3-x-x-(1/x)-(1/3) = 0

1/3-x-x-x^-1-1/3 = 0

-2*x^1-1*x^-1 = 0

(-2*x^2-1*x^0)/(x^1) = 0 // * x^2

x^1*(-2*x^2-1*x^0) = 0

x^1

-2*x^2-1 = 0

-2*x^2-1 = 0

DELTA = 0^2-(-2*(-1)*4)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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