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1/33x+4=x-2
We move all terms to the left:
1/33x+4-(x-2)=0
Domain of the equation: 33x!=0We get rid of parentheses
x!=0/33
x!=0
x∈R
1/33x-x+2+4=0
We multiply all the terms by the denominator
-x*33x+2*33x+4*33x+1=0
Wy multiply elements
-33x^2+66x+132x+1=0
We add all the numbers together, and all the variables
-33x^2+198x+1=0
a = -33; b = 198; c = +1;
Δ = b2-4ac
Δ = 1982-4·(-33)·1
Δ = 39336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{39336}=\sqrt{4*9834}=\sqrt{4}*\sqrt{9834}=2\sqrt{9834}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(198)-2\sqrt{9834}}{2*-33}=\frac{-198-2\sqrt{9834}}{-66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(198)+2\sqrt{9834}}{2*-33}=\frac{-198+2\sqrt{9834}}{-66} $
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