1/3X+35=2x

Solution for 1/3X+35=2x equation:

1/3X+35=2X

We move all terms to the left:

1/3X+35-(2X)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We add all the numbers together, and all the variables

-2X+1/3X+35=0

We multiply all the terms by the denominator


-2X*3X+35*3X+1=0

Wy multiply elements

-6X^2+105X+1=0

a = -6; b = 105; c = +1;
Δ = b2-4ac
Δ = 1052-4·(-6)·1
Δ = 11049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11049}}{2*-6}=\frac{-105-\sqrt{11049}}{-12}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11049}}{2*-6}=\frac{-105+\sqrt{11049}}{-12}
$