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1/3a=7-3a
We move all terms to the left:
1/3a-(7-3a)=0
Domain of the equation: 3a!=0We add all the numbers together, and all the variables
a!=0/3
a!=0
a∈R
1/3a-(-3a+7)=0
We get rid of parentheses
1/3a+3a-7=0
We multiply all the terms by the denominator
3a*3a-7*3a+1=0
Wy multiply elements
9a^2-21a+1=0
a = 9; b = -21; c = +1;
Δ = b2-4ac
Δ = -212-4·9·1
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9\sqrt{5}}{2*9}=\frac{21-9\sqrt{5}}{18} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9\sqrt{5}}{2*9}=\frac{21+9\sqrt{5}}{18} $
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