1/3b+1/4=33/4+3b

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Solution for 1/3b+1/4=33/4+3b equation: 


b in (-oo:+oo)

(1/3)*b+1/4 = 3*b+33/4 // - 3*b+33/4

(1/3)*b-(3*b)+1/4-(33/4) = 0

(1/3)*b-3*b+1/4-33/4 = 0

-8/3*b-8 = 0 // + 8

-8/3*b = 8 // : -8/3

b = 8/(-8/3)

b = -3

b = -3

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