1/3b+10=22

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Solution for 1/3b+10=22 equation: 



1/3b+10=22

We move all terms to the left:

1/3b+10-(22)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

1/3b-12=0

We multiply all the terms by the denominator


-12*3b+1=0

Wy multiply elements

-36b+1=0

We move all terms containing b to the left, all other terms to the right

-36b=-1

b=-1/-36

b=1/36

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