1/3b+11=10

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Solution for 1/3b+11=10 equation:



1/3b+11=10
We move all terms to the left:
1/3b+11-(10)=0
Domain of the equation: 3b!=0
b!=0/3
b!=0
b∈R
We add all the numbers together, and all the variables
1/3b+1=0
We multiply all the terms by the denominator
1*3b+1=0
Wy multiply elements
3b+1=0
We move all terms containing b to the left, all other terms to the right
3b=-1
b=-1/3
b=-1/3

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