1/3b+12=16

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Solution for 1/3b+12=16 equation: 



1/3b+12=16

We move all terms to the left:

1/3b+12-(16)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

1/3b-4=0

We multiply all the terms by the denominator


-4*3b+1=0

Wy multiply elements

-12b+1=0

We move all terms containing b to the left, all other terms to the right

-12b=-1

b=-1/-12

b=1/12

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