1/3b+8=10

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Solution for 1/3b+8=10 equation: 



1/3b+8=10

We move all terms to the left:

1/3b+8-(10)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

1/3b-2=0

We multiply all the terms by the denominator


-2*3b+1=0

Wy multiply elements

-6b+1=0

We move all terms containing b to the left, all other terms to the right

-6b=-1

b=-1/-6

b=1/6

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