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1/3b-(-12)=15
We move all terms to the left:
1/3b-(-12)-(15)=0
Domain of the equation: 3b!=0determiningTheFunctionDomain 1/3b-15-(-12)=0
b!=0/3
b!=0
b∈R
We add all the numbers together, and all the variables
1/3b-3=0
We multiply all the terms by the denominator
-3*3b+1=0
Wy multiply elements
-9b+1=0
We move all terms containing b to the left, all other terms to the right
-9b=-1
b=-1/-9
b=1/9
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