1/3c+10=12

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Solution for 1/3c+10=12 equation:



1/3c+10=12
We move all terms to the left:
1/3c+10-(12)=0
Domain of the equation: 3c!=0
c!=0/3
c!=0
c∈R
We add all the numbers together, and all the variables
1/3c-2=0
We multiply all the terms by the denominator
-2*3c+1=0
Wy multiply elements
-6c+1=0
We move all terms containing c to the left, all other terms to the right
-6c=-1
c=-1/-6
c=1/6

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