1/3c+2/5c-2/3=4/5

Solution for 1/3c+2/5c-2/3=4/5 equation:

1/3c+2/5c-2/3=4/5

We move all terms to the left:

1/3c+2/5c-2/3-(4/5)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R


We add all the numbers together, and all the variables

1/3c+2/5c-2/3-(+4/5)=0

We get rid of parentheses

1/3c+2/5c-2/3-4/5=0

We calculate fractions


125c/675c^2+54c/675c^2+(-250c)/675c^2+(-108c)/675c^2=0

We multiply all the terms by the denominator


125c+54c+(-250c)+(-108c)=0

We add all the numbers together, and all the variables

179c+(-250c)+(-108c)=0

We get rid of parentheses

179c-250c-108c=0

We add all the numbers together, and all the variables

-179c=0

c=0/-179

c=0

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