1/3c+6=2/3(c-12)

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Solution for 1/3c+6=2/3(c-12) equation: 



1/3c+6=2/3(c-12)

We move all terms to the left:

1/3c+6-(2/3(c-12))=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R





Domain of the equation: 3(c-12))!=0

c∈R



We calculate fractions


(3cc/(9c^2c+(-(2*3c)/(9c^2c+6=0

We can not solve this equation

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