1/3c-1/4c+3=7

Solution for 1/3c-1/4c+3=7 equation:

1/3c-1/4c+3=7

We move all terms to the left:

1/3c-1/4c+3-(7)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R


We add all the numbers together, and all the variables

1/3c-1/4c-4=0

We calculate fractions


4c/12c^2+(-3c)/12c^2-4=0

We multiply all the terms by the denominator


4c+(-3c)-4*12c^2=0

Wy multiply elements

-48c^2+4c+(-3c)=0

We get rid of parentheses

-48c^2+4c-3c=0

We add all the numbers together, and all the variables

-48c^2+c=0

a = -48; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-48)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-48}=\frac{-2}{-96}
=1/48
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-48}=\frac{0}{-96}
=0
$