1/3c-1/4c=1/2+0

Solution for 1/3c-1/4c=1/2+0 equation:

1/3c-1/4c=1/2+0

We move all terms to the left:

1/3c-1/4c-(1/2+0)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R


We add all the numbers together, and all the variables

1/3c-1/4c-(+1/2)=0

We get rid of parentheses

1/3c-1/4c-1/2=0

We calculate fractions


(-48c^2)/48c^2+16c/48c^2+(-12c)/48c^2=0

We multiply all the terms by the denominator


(-48c^2)+16c+(-12c)=0

We get rid of parentheses

-48c^2+16c-12c=0

We add all the numbers together, and all the variables

-48c^2+4c=0

a = -48; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-48)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-48}=\frac{-8}{-96}
=1/12
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-48}=\frac{0}{-96}
=0
$