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1/3d+1/5d=1/2
We move all terms to the left:
1/3d+1/5d-(1/2)=0
Domain of the equation: 3d!=0
d!=0/3
d!=0
d∈R
Domain of the equation: 5d!=0We add all the numbers together, and all the variables
d!=0/5
d!=0
d∈R
1/3d+1/5d-(+1/2)=0
We get rid of parentheses
1/3d+1/5d-1/2=0
We calculate fractions
(-75d^2)/60d^2+20d/60d^2+12d/60d^2=0
We multiply all the terms by the denominator
(-75d^2)+20d+12d=0
We add all the numbers together, and all the variables
(-75d^2)+32d=0
We get rid of parentheses
-75d^2+32d=0
a = -75; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·(-75)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*-75}=\frac{-64}{-150} =32/75 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*-75}=\frac{0}{-150} =0 $
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